Hard references are smart--they keep track of reference counts for you, automatically freeing the thing referred to when its reference count goes to zero. If that thing happens to be an object, the object is destructed. See the perlobj manpage for more about objects. (In a sense, everything in Perl is an object, but we usually reserve the word for references to objects that have been officially "blessed" into a class package.)
A symbolic reference contains the name of a variable, just as a symbolic link in the filesystem merely contains the name of a file. The *glob notation is a kind of symbolic reference. Hard references are more like hard links in the file system: merely another way at getting at the same underlying object, irrespective of its name.
"Hard" references are easy to use in Perl. There is just one overriding principle: Perl does no implicit referencing or dereferencing. When a scalar is holding a reference, it always behaves as a scalar. It doesn't magically start being an array or a hash unless you tell it so explicitly by dereferencing it.
References can be constructed several ways.
$scalarref = \$foo; $arrayref = \@ARGV; $hashref = \%ENV; $coderef = \&handler;
$arrayref = [1, 2, ['a', 'b', 'c']];Here we've constructed a reference to an anonymous array of three elements whose final element is itself reference to another anonymous array of three elements. (The multidimensional syntax described later can be used to access this. For example, after the above, $arrayref->[2][1] would have the value "b".)
$hashref = { 'Adam' => 'Eve', 'Clyde' => 'Bonnie', };Anonymous hash and array constructors can be intermixed freely to produce as complicated a structure as you want. The multidimensional syntax described below works for these too. The values above are literals, but variables and expressions would work just as well, because assignment operators in Perl (even within local() or my()) are executable statements, not compile-time declarations.
Because curly brackets (braces) are used for several other things including BLOCKs, you may occasionally have to disambiguate braces at the beginning of a statement by putting a + or a return in front so that Perl realizes the opening brace isn't starting a BLOCK. The economy and mnemonic value of using curlies is deemed worth this occasional extra hassle.
For example, if you wanted a function to make a new hash and return a reference to it, you have these options:
sub hashem { { @_ } } # silently wrong sub hashem { +{ @_ } } # ok sub hashem { return { @_ } } # ok
$coderef = sub { print "Boink!\n" };Note the presence of the semicolon. Except for the fact that the code inside isn't executed immediately, a sub {} is not so much a declaration as it is an operator, like do{} or eval{}. (However, no matter how many times you execute that line (unless you're in an eval("...")), $coderef will still have a reference to the SAM&/I; anonymous subroutine.)
For those who worry about these things, the current implementation uses shallow binding of local() variables; my() variables are not accessible. This precludes true closures. However, you can work around this with a run-time (rather than a compile-time) eval():
{ my $x = time; $coderef = eval "sub { \$x }"; }Normally--if you'd used just sub{} or even eval{}--your unew sub would only have been able to access the global $x. But because you've used a run-time eval(), this will not only generate a brand new subroutine reference each time called, it will all grant access to the my() variable lexically above it rather than the global one. The particular $x accessed will be different for each new sub you create. This mechanism yields deep binding of variables. (If you don't know what closures, deep binding, or shallow binding are, don't worry too much about it.)
$objref = new Doggie (Tail => 'short', Ears => 'long');
$bar = $$scalarref; push(@$arrayref, $filename); $$arrayref[0] = "January"; $$hashref{"KEY"} = "VALUE"; &$coderef(1,2,3);It's important to understand that we are specifically NOT dereferencing $arrayref[0] or $hashref{"KEY"} there. The dereference of the scalar variable happens BEFOR&/I; it does any key lookups. Anything more complicated than a simple scalar variable must use methods 2 or 3 below. However, a "simple scalar" includes an identifier that itself uses method 1 recursively. Therefore, the following prints "howdy".
$refrefref = \\\"howdy"; print $$$$refrefref;
$bar = ${$scalarref}; push(@{$arrayref}, $filename); ${$arrayref}[0] = "January"; ${$hashref}{"KEY"} = "VALUE"; &{$coderef}(1,2,3);Admittedly, it's a little silly to use the curlies in this case, but the BLOCK can contain any arbitrary expression, in particular, subscripted expressions:
&{ $dispatch{$index} }(1,2,3); # call correct routineBecause of being able to omit the curlies for the simple case of $$x, people often make the mistake of viewing the dereferencing symbols as proper operators, and wonder about their precedence. If they were, though, you could use parens instead of braces. That's not the case. Consider the difference below; case 0 is a short-hand version of case 1, NOT case 2:
$$hashref{"KEY"} = "VALUE"; # CASE 0 ${$hashref}{"KEY"} = "VALUE"; # CASE 1 ${$hashref{"KEY"}} = "VALUE"; # CASE 2 ${$hashref->{"KEY"}} = "VALUE"; # CASE 3Case 2 is also deceptive in that you're accessing a variable called %hashref, not dereferencing through $hashref to the hash it's presumably referencing. That would be case 3.
$arrayref->[0] = "January"; $hashref->{"KEY} = "VALUE";The left side of the array can be any expression returning a reference, including a previous dereference. Note that $array[$x] is NOT the same thing as C<$array->[$x]> here:
$array[$x]->{"foo"}->[0] = "January";This is one of the cases we mentioned earlier in which references could spring into existence when in an lvalue context. Before this statement, $array[$x] may have been undefined. If so, it's automatically defined with a hash reference so that we can look up {"foo"} in it. Likewise C<$array[$x]->{"foo"}> will automatically get defined with an array reference so that we can look up [0] in it.
One more thing here. The arrow is optional BETWEEN brackets subscripts, so you can shrink the above down to
$array[$x]{"foo"}[0] = "January";Which, in the degenerate case of using only ordinary arrays, gives you multidimensional arrays just like C's:
$score[$x][$y][$z] += 42;Well, okay, not entirely like C's arrays, actually. C doesn't know how to grow its arrays on demand. Perl does.
The bless() operator may be used to associate a reference with a package functioning as an object class. See the perlobj manpage .
A type glob may be dereferenced the same way a reference can, since the dereference syntax always indicates the kind of reference desired. So ${*foo} and ${\$foo} both indicate the same scalar variable.
Here's a trick for interpolating a subroutine call into a string:
print "My sub returned ${\mysub(1,2,3)}\n";The way it works is that when the ${...} is seen in the double-quoted string, it's evaluated as a block. The block executes the call to mysub(1,2,3), and then takes a reference to that. So the whole block returns a reference to a scalar, which is then dereferenced by ${...} and stuck into the double-quoted string.
People frequently expect it to work like this. So it does.
$name = "foo"; $$name = 1; # Sets $foo ${$name} = 2; # Sets $foo ${$name x 2} = 3; # Sets $foofoo $name->[0] = 4; # Sets $foo[0] @$name = (); # Clears @foo &$name(); # Calls &foo() (as in Perl 4) $pack = "THAT"; ${"${pack}::$name"} = 5; # Sets $THAT::foo without evalThis is very powerful, and slightly dangerous, in that it's possible to intend (with the utmost sincerity) to use a hard reference, and accidentally use a symbolic reference instead. To protect against that, you can say
use strict 'refs';and then only hard references will be allowed for the rest of the enclosing block. An inner block may countermand that with
no strict 'refs';Only package variables are visible to symbolic references. Lexical variables (declared with my()) aren't in a symbol table, and thus are invisible to this mechanism. For example:
local($value) = 10; $ref = \$value; { my $value = 20; print $$ref; }This will still print 10, not 20. Remember that local() affects package variables, which are all "global" to the package.